n^4-(s-x)n^2+2x(35-x)=

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Solution for n^4-(s-x)n^2+2x(35-x)= equation: 


Simplifying
n4 + -1(s + -1x) * n2 + 2x(35 + -1x) = 0

Reorder the terms for easier multiplication:
n4 + -1n2(s + -1x) + 2x(35 + -1x) = 0
n4 + (s * -1n2 + -1x * -1n2) + 2x(35 + -1x) = 0
n4 + (-1n2s + 1n2x) + 2x(35 + -1x) = 0
n4 + -1n2s + 1n2x + (35 * 2x + -1x * 2x) = 0
n4 + -1n2s + 1n2x + (70x + -2x2) = 0

Reorder the terms:
-1n2s + 1n2x + n4 + 70x + -2x2 = 0

Solving
-1n2s + 1n2x + n4 + 70x + -2x2 = 0

Solving for variable 'n'.

The solution to this equation could not be determined.

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